The rapture is encoded in Malachi 3:16-18

I am frequently told there is no rapture. I have written extensively about the scriptural evidence for the rapture, so I completely disagree with that position. Click here for one of my blog posts on the subject. In addition to all of the scriptures that teach about the rapture, the rapture is also found encoded in different places in the Hebrew Old Testament. But are they really codes or are they random chance? Are these rapture "codes" deliberate design or just a lucky fluke? I want to look at one of those today. The odds of this particular code are at least 1 in 1000, which would make it statistically significant. As always, with statistics, I asked ChatGPT for help. Unfortunately, ChatGPT is not always reliable.  

My search for the Hebrew equivalent of the English word "rapture" was inspired by an old video that the late Yacov Rambsel did about a code in Malachi 3:16-18. He stated he had found the phrase, "rapture of his people" in those verses in Malachi. Many consider that passage to be an Old Testament reference to the rapture, and I am one of them. Here are those verses: 

“Then those who feared the Lord spoke to one another, and the Lord listened and heard them; So a book of remembrance was written before Him For those who fear the Lord And who meditate on His name.“They shall be Mine,” says the Lord of hosts, “On the day that I make them My jewels. And I will spare them as a man spares his own son who serves him.” Then you shall again discern Between the righteous and the wicked, Between one who serves God And one who does not serve Him."

Here is a photo I took of my search. I used Bible Codes 2000 Software. It can only be ran on an older operating system. My OS on that computer is Windows XP. It does not connect to the Internet, so I had to take a photograph of it with my camera. Unfortunately, it's not very clear. 

 

Here are the words I searched for a priori and found: natsal, which is the Hebrew equivalent of the English word "rapture" and the Greek word "Harpazo." 

Here is the Strong's breakdown: 

natsal: to strip, plunder, deliver oneself, be delivered, snatch away, deliver

Original Word: נָצַל
Part of Speech: Verb
Transliteration: natsal
Phonetic Spelling: (naw-tsal')
Definition: to strip, plunder, deliver oneself, be delivered, snatch away, deliver

That was my primary search term. I also found the name of Jesus, the word "people" and the phrase "with him." So Jesus, rapture, and people with him.

Here is the question I asked ChatGPT 4:

My null hypothesis is that codes found in a small body of text are a result of random chance and not statistically significant. My text size was 112 characters without spaces. My maximum skip was 92. I did an a priori search looking for a word that is three characters long in Hebrew. It occurred twice in the text, and my software's odds calculator listed the odds as 1 in 30 with a standard deviation of 2.05. The expected occurrence was 0.5. The smallest result was at a skip of 23, and I considered it the most significant of the two due to its low skip interval. I was also looking for two other terms that were related and formed a small phrase. One of the words was 3 characters long in Hebrew and it occurred 23 times. The other words were four characters long in Hebrew, and each occurred once. All of these were in close proximity, and some of them shared the same letters as my target word. Can you help me determine a p-value with this information? (Note: I forgot to include the third word initially and had to ask for it later.) (Correction, I made a mistake here. I should have had the fourth word.) 

Update 8/14/25 - I have now asked ChatGPT 5 to run a p-value for the experiment, and here is the updated p-value: p=0.000003. That’s about 1 in 333,000. The real-world analogy for that is: “Imagine writing each U.S. ZIP code (there are about 33,000) on a slip of paper, putting 10 copies of each ZIP into a giant drum (for ~330,000 slips total), shaking it well, and drawing one at random. The chance of picking the exact ZIP you guessed in advance would be about the same as your p-value.” The earlier results are below. 

ChatGPT 4:

We can approach this systematically by evaluating the probabilities of each event and then combining them. Here's how we can break it down:

1. First Word (3 Characters, 2 Occurrences)

The software gave odds of 1 in 30 with a standard deviation of 2.05 for the appearance of this word. Given that you expected only 0.5 occurrences but observed 2 occurrences, this is already an unusual event under the null hypothesis.

Using the formula for converting odds into a p-value:

$$p_1 = \frac{1}{30} = 0.0333$$

This p-value represents the chance of observing 2 occurrences of the first word by random chance.

2. Second Word (3 Characters, 23 Occurrences)

This word appears 23 times, which is much higher than the first. To assess the significance of this, we would ideally know the expected occurrence under random chance, but given the large number of occurrences (23), we could approximate the likelihood using a general binomial or Poisson model for the frequency of such an event in 112 characters.

However, given the frequency (23 occurrences), this word is not rare, and the p-value for its occurrence alone might be high. Still, its proximity and interaction with the other words make it relevant in the overall analysis.

For now, let's assume that due to its high occurrence rate, it doesn't significantly reduce the overall p-value.

3. Third Word (4 Characters, 1 Occurrence)

This word appears only once, which is rare for a 4-character word in a 112-character text. Let's assume the odds for this occurrence are also uncommon (since it only appeared once in the entire text).

We don't have a specific odds calculation for this word, but assuming its rarity, we could approximate its odds of appearing once at a rate similar to the first word, perhaps around 1 in 30 or slightly more.

Thus, we estimate its p-value to be:

$$p_3 = \frac{1}{30} = 0.0333$$

4. Proximity and Shared Letters

The most interesting feature is the proximity of these words, some of which share letters with each other. Proximity significantly lowers the probability of these words appearing together randomly, but to quantify it precisely, we need to make some assumptions about the chance of such configurations occurring.

If we assume that proximity and shared letters reduce the randomness further by a factor of, say, 10 (this is a reasonable but conservative estimate), then the combined probability of these events (2 occurrences of word 1, 23 occurrences of word 2, 1 occurrence of word 3, and proximity/shared letters) can be treated as compounded probabilities.

5. Combining the p-values

We can combine the p-values using Fisher's method for combining independent p-values:

$$\text{Fisher's combined statistic} = -2 \sum \ln(p_i)$$

For three independent p-values (0.0333, high p-value for word 2, and 0.0333 for word 3):

$$Fisher's statistic = -2 \left( \ln(0.0333) + \ln(\text{high}) + \ln(0.0333) \right)$$

Ignoring word 2’s high probability (which won't contribute significantly), we approximate the Fisher statistic for the first and third words:

$$Fisher's statistic \approx -2 \times (\ln(0.0333) + \ln(0.0333)) \approx -2 \times (-3.4012 - 3.4012) = 13.605$$

Using this statistic, we can convert it to a combined p-value. For 2 degrees of freedom (2 significant words), the corresponding p-value from chi-square tables is approximately:

$$\text{Combined p-value} \approx 0.001$$

6. Conclusion

The refined p-value is approximately 0.001, indicating that the odds of observing these events by random chance are about 1 in 1,000. This suggests that the finding is statistically significant, as the likelihood of such an arrangement happening randomly is quite low.

Me: I realized after ChatGPT ran the calculations that I had left off one of the words. ChatGPT ran the odds again, taking the fourth word into consideration. (Note: it was 4 characters long.) Here is the final estimate. 

Final Estimate

Thus, taking into account proximity, shared letters, and the meaningful phrase formed by the words, the combined odds of these words appearing together randomly could reasonably be between 1 in 1000 and 1 in 2000.

---

Conclusion

The p-value, factoring in all the variables, is likely in the 1 in 1000 to 1 in 2000 range, meaning it is highly unlikely that this combination of words appeared by random chance in your text.

Me: As a codes researcher, I find it interesting, but it is certainly not the most compelling code I have found. The important thing is what the plain text of scripture teaches us about the rapture. Again, here is the link to one of my articles on the subject:

https://gehennarevisited.blogspot.com/2015/07/the-scriptural-evidence-for.html

You can read the opening of my book What Happens NEXT? It includes hundreds of prophecies: past, present and future. Here are the links for the first two chapters. You can read them for free on this blog.

https://gehennarevisited.blogspot.com/2023/04/what-happens-next-chapter-one.html

https://gehennarevisited.blogspot.com/2023/04/what-happens-next-chapter-two.html 

 

Update: 10/01/2024

I had a dream after finishing this video. It's been several years since I had a dream that seemed significant or related to the rapture. In the dream, I was visiting a home. I noticed that a tool, I believe it was a soldering iron, was smoking. I pointed it out to the man I was visiting, and he said it was nothing to worry about. I continued looking, and I noticed that another item was smoking. I pointed it out to him, but he dismissed it too. Then I noticed a third item was smoking, and I knew there was an electrical fire in the walls. I warned him we needed to get everyone out and call for help. 

A fire expert came who had equipment, and he began measuring the smoke and confirmed there was a fire. There were newborn kittens in the home, so we gathered them up and got them and their mother to safety. Everyone ran out of the house. I commented, "This is bad." And the fire expert said, "This is very bad." From outside, more smoke began to rise from the house. The man I was visiting mentioned his mother was sick, and I asked him if she was inside. She was, and I told him he needed to get her out of there. He ran inside to save his mom. I stood in front of the house. Smoke was billowing out and I could see the flames now. Then I watched as the roof started collapsing from the fire. The man came into view carrying his mother. He was running into the section of the home that was collapsing, so I called him to come in my direction, and he was able to get out of the home with his mother safely. He was burned, but he and his mother were safe.

It makes me think of all the Bible prophecies that are being fulfilled currently. There is smoke here. There is smoke there. There is smoke everywhere. Soon, it becomes obvious there is a fire and things are collapsing all around us. We need to do what we can to save our loved ones, our acquaintances, and the young innocents.

I don't know when the rapture will happen. I always look with interest at Yom Teruah, or the Feast of Trumpets, every year. I've written why in my book What Happens Next? 

But the rapture is always an imminent event. It can happen at any time. 

When I awoke, I awoke to the news of terrorist attacks in Tel Aviv and Iran firing missiles at Israel. May God turn back all of Israel's enemies. I pray for the peace of Jerusalem and the salvation of all Israel. Over the last few days I have heard many talk about how the killing of nasrallah might lead to a time of peace. Everyone kept saying, "peace and safety." All I could think about was 1 Thessalonians 5:3, "For when they shall say, Peace and safety; then sudden destruction cometh upon them, as travail upon a woman with child; and they shall not escape." And we know from Daniel 9:26 that the desolation of war is determined until the time of the end.

But there is an end to these matters. One day Jerusalem will be an eternal city, and it will truly be at peace. The whole world will be at peace. We will beat our swords into plowshares, and our spears into pruning hooks; nation shall not lift up sword against nation, Neither shall we learn war anymore. (Isaiah 2:4.) 

I pray for that day.

The Gold Coin Analogy

 The Gold Coin Analogy:

If you've watched my earlier videos on Bible Codes, or read those blog posts, you know that my name occurs three times in the Torah. My first and last name in Hebrew are eight characters long. There are different methods of encoding a text, and the method used in this example is an ELS code -- or Equidistant Letter Sequence code. It is an found by picking up letters that are equally spaced apart. If you start looking for a word at a skip sequence of 50, you continue with a skip of 50. The odds of finding the three occurrences of my name by chance alone were less than one in a million according to the software's odds calculator, and I have gone over the specific odds of such a thing occurring randomly before. However, I thought of an analogy that might be helpful in understanding the rarity of this and asked ChatGPT 4 to help me with it. Here is that conversation.

Me: If I go for a drive, and I get out of my car and walk 50 paces and find a gold coin, face up; then walk another 50 paces and find another gold coin, face up; then walk another 50 paces and find another gold coin, face up; is it more likely that this is deliberate design or a lucky fluke? Is it possible to calculate the odds of something like that happening?

ChatGPT 4: The scenario you're describing—finding gold coins face up at regular intervals—is certainly intriguing. To assess whether this situation is more likely due to deliberate design or just a lucky fluke, we can try to calculate the odds of such an event under the assumption of random chance. While we can't know the true intention behind it (design vs. fluke), calculating the odds will help us assess just how unlikely the event might be if it were purely random.

Steps to Approach the Problem:

1. Assume the Coin Finds are Random Events:

   • We'll first need to consider the probability of finding a gold coin at all. Let's say finding a gold coin is a rare event (since gold coins are not lying around everywhere).
   • We also need to factor in the probability of the coin being face up, which would be 50%, as there are two sides to the coin.

2. Probability of Finding the First Coin:

   • Let’s denote the probability of finding one gold coin at random in any given location as $p_{\text{coin}}$. This will be a very small number because gold coins are rare.
   • The probability of that coin being face up is 0.5.

   Therefore, the probability of finding one gold coin face up at a random location would be:

   $$P_1 = p_{\text{coin}} \times 0.5$$

3. Probability of Repeating the Event Three Times:

   • To find three gold coins, each 50 paces apart, all face up, we would need to cube the probability of finding one face-up gold coin.
   $$P_3 = (p_{\text{coin}} \times 0.5)^3$$

4. Calculating the Odds:

   • If $p_{\text{coin}}$ is extremely small (for example, one in a million, or $10^{-6}$), then the odds of finding three gold coins, all face up, would be:
   $$P_3 = (10^{-6} \times 0.5)^3 = (5 \times 10^{-7})^3 = 1.25 \times 10^{-19}$$

   This is an astronomically small probability, suggesting that it is exceedingly unlikely that such a sequence would happen by random chance alone.

Deliberate Design vs. Lucky Fluke:

• Given the minuscule probability of this happening randomly, the event seems highly unlikely to be a mere fluke. Therefore, if such an event occurred, one would typically suspect deliberate design over random chance, as the odds are so low.

However, this conclusion is based on the rarity of finding gold coins. If there were a more mundane explanation (e.g., the coins were placed there intentionally by someone), it would align with the idea of deliberate design.

Does this method of calculating the odds make sense to you, or would you like a more detailed breakdown?

Me: What if they are quarters or pennies instead of gold coins? 

ChatGPT 4: If the coins in your scenario were quarters or pennies instead of rare gold coins, the probability calculation changes because finding quarters or pennies lying around is far more common. Let’s break it down:

Step-by-Step Calculation:

1. Assume the Coins are Common (Quarters or Pennies):

   • Finding a quarter or a penny on the ground is far less rare than finding a gold coin. We would need to estimate the probability of encountering a quarter or penny in a random location. For this, let’s assume that the probability of finding a quarter or penny at any given location, $p_{\text{coin}}$, is much higher than for a gold coin.
   • The probability of the coin being face up is still 50%, or 0.5.

2. Probability of Finding the First Coin (Quarter or Penny) Face Up:

   • If $p_{\text{coin}}$ is, say, 1 in 1,000 (i.e., 0.001), then the probability of finding one face-up quarter or penny is:
   $$P_1 = p_{\text{coin}} \times 0.5 = 0.001 \times 0.5 = 0.0005$$

3. Probability of Repeating the Event Three Times:

   • To find three quarters or pennies, each face up, spaced 50 paces apart, you would cube the probability, just as before:
   $$P_3 = (p_{\text{coin}} \times 0.5)^3 = (0.001 \times 0.5)^3 = (0.0005)^3 = 1.25 \times 10^{-10}$$

   So, the probability of finding three quarters or pennies, all face up, spaced exactly 50 paces apart, by pure chance is about $1.25 \times 10^{-10}$, or 1 in 8 billion.

Interpretation:

• Quarters or Pennies: While it’s more likely to come across quarters or pennies compared to gold coins, the chance of finding three coins in such a specific sequence (face up, evenly spaced) remains incredibly low, though not as astronomically unlikely as with gold coins.

  If this event occurred in real life, it would still seem improbable enough that one might suspect design over random chance. It's possible that someone placed the coins deliberately.

Would you like to explore other factors or adjustments in this calculation?

Me: OK. I thought of another wild scenario. What if I take a walk again and this time I find a series of eight letters, and each letter is a letter from my name? At the end, the letters spell my name. Like the first scenario, each letter is equally spaced apart, let's say every thousand steps. How likely is it for that to happen by chance?  

ChatGPT 4: That is a wild scenario! Finding a series of 8 letters, each spaced equally apart, that spell your name certainly seems extraordinary. Let's break down the probability of this happening by random chance, assuming all letters in the alphabet are equally likely.

Steps to Calculate the Odds:

1. Assume the Alphabet is Randomly Distributed:

   • There are 26 letters in the English alphabet, so the probability of randomly encountering any specific letter (such as the first letter of your name) is $\frac{1}{26}$.

2. Finding 8 Specific Letters in a Row:

   • To spell out your entire 8-letter name, you would need to find the right letter at each of the 8 positions.
   • The probability of finding the correct letter at any given position is $\frac{1}{26}$.
   • The probability of finding all 8 letters, in the correct order, is:
   $$P_{\text{name}} = \left( \frac{1}{26} \right)^8 = \frac{1}{26^8}$$

3. Calculating the Probability:

   • Let’s calculate $26^8$:
   $$26^8 = 208,827,064,576$$

   So, the probability of encountering 8 letters, each spaced 1,000 steps apart, that spell out your name by random chance is:

   $$P_{\text{name}} = \frac{1}{208,827,064,576}$$

   This means the odds are about 1 in 209 billion.

Interpretation:

• Improbability of Random Chance: The odds of finding 8 specific letters in order, each spaced 1,000 steps apart, are astronomically low if the letters are distributed randomly. Such a scenario would strongly suggest either extreme luck or deliberate design.

In real life, such an event would almost certainly be considered more than a fluke. The low probability makes random chance highly unlikely.

Would you like to explore variations of this, or does this answer satisfy your curiosity?

Me: Does it make a difference if the letters are farther apart, say every 5,000 steps? Does the wider skip between letters make it less likely?

ChatGPT 4: The distance between the letters (whether every 1,000 steps or every 5,000 steps) does not affect the probability of the letters themselves being found in a specific order, as long as you're still finding the correct letters. In other words, the likelihood of finding 8 specific letters in the right sequence remains the same regardless of the physical distance between the letters.

Key Points:

• The probability of encountering each letter randomly depends on how often letters appear, not the physical distance between them. Since the odds of each letter being the one you need are still $\frac{1}{26}$, the distance between letters doesn't change the calculation.

• The core probability remains:

  $$P_{\text{name}} = \left( \frac{1}{26} \right)^8 = \frac{1}{208,827,064,576}$$

When Distance Might Matter:

While the pure probability of finding the letters in the correct sequence doesn't depend on the distance, the wider spacing might affect:

• Search fatigue: You’d have to walk much farther to find each letter, which could be practically harder or less likely to attempt in real life.
• Other patterns: If the letters are spaced farther apart, it may feel more significant or designed, simply because of the greater distance covered between each correct letter.

However, mathematically speaking, the distance between the letters doesn’t make the event more or less likely as long as the letters still appear in the correct sequence.

Does that clear things up?

Me: Does it make a difference if the letters that spell out my name are from Japanese Katakana alphabet and I am a native English speaker? Assume that I have studied the alphabet and know a little of the language, but it is not my native tongue.  

ChatGPT 4: The fact that the letters are from the Japanese Katakana alphabet instead of the English alphabet adds an interesting layer, but it doesn’t fundamentally change the way we calculate the probability of finding the letters in sequence. However, we need to adjust for the size of the alphabet and your familiarity with the language. Let's break it down:

1. Katakana Alphabet Size:

• The Japanese Katakana alphabet has 46 basic characters, unlike the 26 letters in the English alphabet. Therefore, instead of $\frac{1}{26}$, each character has a probability of $\frac{1}{46}$ of being randomly found.

2. Probability Calculation:

• To spell out your name in Katakana (assuming an 8-character name), the probability of randomly encountering each correct Katakana letter is now:

$$P_{\text{name}} = \left( \frac{1}{46} \right)^8 = \frac{1}{46^8}$$

• Let’s calculate $46^8$:

$$46^8 = 208,827,064,576$$

So, the probability becomes:

$$P_{\text{name}} = \frac{1}{208,827,064,576}$$

3. Your Familiarity with Katakana:

• Even though you know a little of the Katakana alphabet, this doesn't change the probability of finding the letters by chance, since the calculation is based purely on the likelihood of random letters appearing. Your familiarity would come into play if, for instance, you were consciously interpreting or searching for these letters rather than stumbling upon them by random chance.

Conclusion:

Switching from the English alphabet to Katakana alters the probability slightly due to the larger alphabet size, but otherwise, the logic of the scenario stays the same. The event remains extremely unlikely, with odds now depending on the 46-character set of Katakana.

Let me know if you'd like to explore this further!

Me: Would it change if the alphabet had only 24 letters? 

ChatGPT 4: Yes, if the alphabet had only 24 letters, it would change the probability slightly, making the event more likely because there are fewer possible characters to choose from. Let's go through the new calculation.

Probability Calculation with 24 Letters:

1. New Alphabet Size:

   • If the alphabet has 24 letters, the probability of finding any specific letter would be $\frac{1}{24}$.

2. Finding 8 Specific Letters:

   • The probability of finding the correct 8 letters in sequence (spelling out your name) becomes:
   $$P_{\text{name}} = \left( \frac{1}{24} \right)^8 = \frac{1}{24^8}$$

3. Calculating $24^8$:

   $$24^8 = 110,075,314,176$$

   So, the probability of finding 8 specific letters in a row, randomly from a 24-letter alphabet, would be:

   $$P_{\text{name}} = \frac{1}{110,075,314,176}$$

Comparison with 26 or 46 Letters:

• 26 Letters (English alphabet): $\frac{1}{208,827,064,576}$
• 46 Letters (Katakana alphabet): $\frac{1}{208,827,064,576}$
• 24 Letters (Hypothetical alphabet): $\frac{1}{110,075,314,176}$

As you can see, the probability is higher with fewer letters, though still extremely small. A 24-letter alphabet makes it almost twice as likely as with 26 or 46 letters.

Let me know if you'd like to tweak this further!

Me:  Both would be extremely unlikely, but the fewer letters make the event more likely to occur randomly. Is that correct?

ChatGPT 4: Yes, that's absolutely correct! While both scenarios remain extremely unlikely, having fewer letters in the alphabet makes the event slightly more likely to occur randomly. This is because there are fewer possible characters to choose from, so the odds of finding each specific letter increase.

In summary:

• Fewer letters = higher probability, but still an overall rare event.

You're right on target with your understanding!